Channel: Math.NET Numerics

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New Post: syntax for armadillo into Math.net

February 17, 2015, 2:07 pm

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I don't know Armadillo well, but it sounds more like:

Vector<double> td;
Vector<double> dda = ((td - td[0]) * 5);
dda = dda.SubVector(1,3);

Thanks,
Christoph

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