Quantcast
Channel: Math.NET Numerics
Viewing all articles
Browse latest Browse all 971

New Post: syntax for armadillo into Math.net

$
0
0
I don't know Armadillo well, but it sounds more like:
Vector<double> td;
Vector<double> dda = ((td - td[0]) * 5);
dda = dda.SubVector(1,3);
Thanks,
Christoph

Viewing all articles
Browse latest Browse all 971

Trending Articles